Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is none, oncePerWeek, severalPerWeek or daily.
Build a proper factor for the responses below and store it in a variable w.
Print the factor.
Write the code to count the numbers of occurrences of each level and print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek oncePerWeek <NA>
[9] none none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 × 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the results.
Next, understand why an error is generated and use replace argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor w from it.
Finally, count the numbers of occurrences of each level in w.
Ensure, that levels are in order provided in the variable lvl.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "none" "oncePerWeek" "severalPerWeek"
sample( lvs, 3 )
[1] "daily" "none" "severalPerWeek"
sample( lvs, 3 )
[1] "daily" "none" "severalPerWeek"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] none oncePerWeek oncePerWeek none severalPerWeek none daily daily
[9] oncePerWeek daily none daily severalPerWeek none oncePerWeek oncePerWeek
[17] severalPerWeek severalPerWeek none oncePerWeek none oncePerWeek severalPerWeek daily
[25] oncePerWeek oncePerWeek none daily severalPerWeek none daily daily
[33] daily daily oncePerWeek severalPerWeek none none oncePerWeek none
[41] none severalPerWeek severalPerWeek oncePerWeek severalPerWeek none oncePerWeek daily
[49] oncePerWeek severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek oncePerWeek
[57] severalPerWeek severalPerWeek none daily daily oncePerWeek severalPerWeek oncePerWeek
[65] severalPerWeek oncePerWeek oncePerWeek oncePerWeek daily none daily oncePerWeek
[73] oncePerWeek none none severalPerWeek oncePerWeek severalPerWeek daily severalPerWeek
[81] none none none oncePerWeek oncePerWeek none daily daily
[89] severalPerWeek severalPerWeek oncePerWeek oncePerWeek none none severalPerWeek none
[97] daily severalPerWeek daily daily
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 × 2
f n
<fct> <int>
1 none 27
2 oncePerWeek 30
3 severalPerWeek 22
4 daily 21
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its levels.
The factor w from the previous exercise will be then shown in this order: none, oncePerWeek, severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed: daily, severalPerWeek, oncePerWeek, none.
Apply to w one of the fct_ functions from the tidyverse library to produce a factor w2 with the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 × 2
f n
<fct> <int>
1 daily 21
2 severalPerWeek 22
3 oncePerWeek 30
4 none 27